Exam 2 2009 - CHM 2120A Spectroscopy and Carbonyl Chemistry Version A Exam 2 Name Student Number MULTIPLE CHOICE Choose the one alternative that

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CHM 2120A Version A Exam 2 Spectroscopy and Carbonyl Chemistry Name___________________________________ Student Number_____________________________________ MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question 1) Determine the number of signals for 4 - methyl - 1 - propylbenzene in the 1 H NMR spectrum. A) 4 B) 8 C) 7 D) 5 E) 6 1) 2) What is/are the major product(s) of the following reaction? A) B) C) D) E) 2) 1
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3) The compound: can form a hemiacetal by reacting with itself in solution. What is the structure of this hemiacetal? A) I B) II C) III D) IV E) V 3) 4) What splitting pattern is observed in the proton NMR spectrum for the indicated hydrogens? CH 3 OCH 2 CH 2 OCH 3 A) triplet B) quartet C) septet D) doublet E) singlet 4) 5) Identify the product for the reaction. A) B) C) D) E) 5) 2
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6) Which of the following compounds is methyl formate? A) B) C) D) E) 6) 7) Which of the following reagents would reduce carboxylic acids and esters into alcohols? A) H 2 /Raney Ni B) Na/NH 3 C) 1.LiAlH 4 /2.H 3 O + D) Zn(Hg)/H + E) 1.NaBH 4 /2.H 3 O + 7) 8) Which of the following protons gives an NMR signal with the highest chemical shift value (farthest downfield)? (CH 3 ) 2 CH O CH 2 CH 2 CH 3 1 2 3 4 5 A) 1 B) 2 C) 3 D) 4 E) 5 8) 9) In the infrared spectrum, a compound of formula C 4 H 8 O gave an absorption band at 1720 cm
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This note was uploaded on 01/22/2011 for the course CHM 2120 taught by Professor Dr.flynn during the Winter '10 term at University of Ottawa.

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Exam 2 2009 - CHM 2120A Spectroscopy and Carbonyl Chemistry Version A Exam 2 Name Student Number MULTIPLE CHOICE Choose the one alternative that

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