Tutorial 2 Notes

# Tutorial 2 Notes - CHM2132 Tutorial notes for Sept 18th...

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2 q BA = ! U BA " w BA = " 50 J " 20 J = " 70 J Since q AB is negative, heat is being liberated. c) If U D - U A = 40 J then what is the heat of going from A to D and from D to B? First we must recognize that the energy term that we were given was Δ U AD = 40 J. As we already know the energy of going from A to B we can calculate the energy for the remaining step in the cycle: ! U AB = ! U AD + ! U DB ! U DB = ! U AB " ! U AD = 50 J " 40 J =10 J Now in order to use this information to find the heat of steps AD and DB, we must
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Tutorial 2 Notes - CHM2132 Tutorial notes for Sept 18th...

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