This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: x2  mv x1 R y ∆ t = mv y2mv y1 R x = mv x2 / ∆ t R y = mv y2 / ∆ t ( 29 001 . / 25 cos 150 2 . 32 16 / 62 . 1 = x R ( 29 001 . / 25 sin 150 2 . 32 16 / 62 . 1 = y R R x = 427.5 lb R y = 199.3 lb Solve R = 471.7 lbs Could also set our axes along the direction of v∫ 2 1 t t dt F R 1 2 v m v m R R= Most of the time the impact forces are much greater than the weight of the object, so we can neglect mg. You can either break it into components for the impulse momentum equation, or break it up later – let’s start by writing equations in the x and y. x y mv x = mv y = 0 + 2 v m R = ∆ t...
View
Full Document
 Spring '05
 staff
 Force, Momentum, Ry, Golf Shot, oz golf ball

Click to edit the document details