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Unformatted text preview: x2  mv x1 R y t = mv y2mv y1 R x = mv x2 / t R y = mv y2 / t ( 29 001 . / 25 cos 150 2 . 32 16 / 62 . 1 = x R ( 29 001 . / 25 sin 150 2 . 32 16 / 62 . 1 = y R R x = 427.5 lb R y = 199.3 lb Solve R = 471.7 lbs Could also set our axes along the direction of v 2 1 t t dt F R 1 2 v m v m R R= Most of the time the impact forces are much greater than the weight of the object, so we can neglect mg. You can either break it into components for the impulse momentum equation, or break it up later lets start by writing equations in the x and y. x y mv x = mv y = 0 + 2 v m R = t...
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This note was uploaded on 01/22/2011 for the course ME 212 taught by Professor Staff during the Spring '05 term at Cal Poly.
 Spring '05
 staff

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