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Unformatted text preview: j m v m t F A A A B A 20 2= i m v m t F B B B A B ) 30 ( 1= What is true about F AB and F BA ? They are equal and opposite. Now, substitute F BA = F AB and add the two equations above together. j m v m t F A A A B A 20 2= i m v m t F B B B B A ) 30 ( 1= j m i m v m v m A B B B A A 20 ) 30 ( 2 2+ = This is essentially the derivation for Eq 3/28 What is true about v A2 and v B2 ? They are the same so call it v 2 . Substitute and solve j m i m v m m A B B A 20 ) 30 ( ) ( 2+ = ) ( 3 . 10 55 . 14 ) ( 20 ) 30 ( 2 mph j i m m j m i m v B A A B += + += Careful with units you would need to divide the weights by g, but they would end up cancelling in the equation. Same for the mph conversion....
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 Spring '05
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