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Unformatted text preview: velocity. Must consider direction as well 2 / 9 ) ( / 12 s in a a s in v v C t D C D = = = = Note that the radius of the inner pulley is 3 in, can you determine and at t=0? sCW rad w r v D / 4 = = sCW rad r a t D / 3 ) ( = = Since the acceleration is constant we can determine the angular velocity and Number of revolutions at t=2 s sCW rad t / 10 2 * 3 4 = + = + = rev rad rev N radCW t t 23 . 2 2 1 14 2 1 2 = = = + = Now find the motion of load B s in v r v B B / 50 = = in y r y B B 70 = = Lastly find the acceleration at D. 2 / 9 ) ( ) ( s in a a a t D C t D = = 2 2 / 48 ) ( ) ( s in j a j r a n D D n D == sec / 48 9 in j i a D =...
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 Spring '05
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