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ABC can be modeled as a single rigid body.
Its
mass is 300 kg and the moment of inertia about
its center of mass is I = 360 kgm
2
.
Starting from
rest with its CG 2 meters above the ground, the
hydraulic cylinder pushes the arm ABC to the
current position.
At this position, the angular
velocity of the arm is 1.4 rad/sec (CCW) and its
angular acceleration is 0.6 rad/s
2
.
How much
work did the hydraulic cylinder exert on the arm?
+ V
g1
e1
+ U
12
= T
2
+ V
g2
+ V
What equation, and what terms are zero?
Okay for I
A
, it is a fixed axis of rotation
Is it okay to use I
A
?
This reduces to
Solve for U.
T
2
= ½ mv
G
2
+ ½ I
G
ϖ
2
= ½ 300 v
G
2
+ ½ 360
ϖ
2
v
G
= v
A
+
ϖ
x r = r
ϖ
= sqrt(1.8
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This note was uploaded on 01/22/2011 for the course ME 212 taught by Professor Staff during the Spring '05 term at Cal Poly.
 Spring '05
 staff
 Moment Of Inertia

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