EX24.1 - BarWheelPiston

EX24.1 - BarWheelPiston - 1 = 60º θ 2 = 0º ω 2...

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3. The 4 kg uniform slender bar is pinned to a 2 kg slider at A and to a 4 kg homogeneous cylindrical disk at B. Neglect the friction force on the slider and assume that the disc rolls without slip. If the system is released from rest with θ = 60, what is the bar’s angular velocity when θ = 0? Do V g1 Do T 2 How do you relate v and ϖ ? Lots and lots of kinematics – try it. Still need v G of the bar AB Sub into WE equation above, solve for ϖ . What type of problem? Two different positions and velocity - WE Find: Given: m A =2 kg, m AB =4 kg, m B =4 kg, ω 1 = 0.0 rad/s, Rolls without slip, θ
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Unformatted text preview: 1 = 60º, θ 2 = 0º ω 2 Reflection: Each part of the system has kinetic energy; the wheel and disc have both rotational and translational energy. We could solve this out as a function of θ and solve for any position. We could also do out the Newton’s 2 nd law relationships to look at The wheel rolls without slip, so v = R ϖ Now can relate points A and B using ϖ AB At the instant when θ = 0, the disc has rolled as far as it can to the right – now it will stop and start moving back to the left. 1 G G Slider Bar Disk...
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This note was uploaded on 01/22/2011 for the course ME 212 taught by Professor Staff during the Spring '05 term at Cal Poly.

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