Unformatted text preview: 1 = 60º, θ 2 = 0º ω 2 Reflection: Each part of the system has kinetic energy; the wheel and disc have both rotational and translational energy. We could solve this out as a function of θ and solve for any position. We could also do out the Newton’s 2 nd law relationships to look at The wheel rolls without slip, so v = R ϖ Now can relate points A and B using ϖ AB At the instant when θ = 0, the disc has rolled as far as it can to the right – now it will stop and start moving back to the left. 1 G G Slider Bar Disk...
View Full Document
This note was uploaded on 01/22/2011 for the course ME 212 taught by Professor Staff during the Spring '05 term at Cal Poly.
- Spring '05