Unformatted text preview: problem? Write out your equation. Note: Some books use L for linear momentum.-0.7(360*9.81) t = 0 – (320+360) (13.18) 2 3 3 v m v m dt F t m m m-= ∫ 2 Let call the velocity right after impact v 2 , and the velocity after it stops v 3. Now what equation do I use? Solve it! Solution: Problem Type: Find: Given: m cage = 320 kg, v1=28 m/s, m chain =360 kg, μ=0.7 Time t, to stop the cage Has initial speed and then an impulse of friction force. Try impulse momentum IC9.2 Emergency Evacuation Device 2 2 1 ) ( v m m v m v m G G chain cage chain chain cage cage + = + = Solve Reflection: Seems like a reasonable time for slowing down although I am not sure I would want to rely on chain friction? What if it is cold and icy and μ was much smaller?...
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This note was uploaded on 01/22/2011 for the course ME 212 taught by Professor Staff during the Spring '05 term at Cal Poly.
- Spring '05