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IC16.1-Car_Weight_Distribution

# IC16.1-Car_Weight_Distribution - Max acceleration means...

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Given: A 1650 kg car, coefficient of static friction between rear driving wheels is 0.8. You can neglect the rolling friction of the front wheels, and the mass of the front and rear wheels is negligible compared to the mass of the car. Find the normal forces N A and N B under the condition of maximum acceleration. ma Gy ma Gx I α x y E of M. x y M Algebra What if decided to do moments about wheel A?
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Unformatted text preview: Max acceleration means that the friction force is μ s N A-μ N = ma Gx = 0.4(165029(μ s N B )/1650 N A = 6.85 kN B IC15.2 Car Weight Distribution Solution: Problem Type: Find: Given: Draw FBD, MAD What is your first step? M car = 1650 kg, μ=0.8, Weight on Front and Rear Wheels Newton’s second law, Rigid Body Translation...
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