{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}


IC16.1-Car_Weight_Distribution - Max acceleration means...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Given: A 1650 kg car, coefficient of static friction between rear driving wheels is 0.8. You can neglect the rolling friction of the front wheels, and the mass of the front and rear wheels is negligible compared to the mass of the car. Find the normal forces N A and N B under the condition of maximum acceleration. ma Gy ma Gx I α x y E of M. x y M Algebra What if decided to do moments about wheel A?
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Max acceleration means that the friction force is μ s N A-μ N = ma Gx = 0.4(165029(μ s N B )/1650 N A = 6.85 kN B IC15.2 Car Weight Distribution Solution: Problem Type: Find: Given: Draw FBD, MAD What is your first step? M car = 1650 kg, μ=0.8, Weight on Front and Rear Wheels Newton’s second law, Rigid Body Translation...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online