L18-IC1-hacksaw - 5/150 Given: The blade of this hacksaw is...

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5/150 Given: The blade of this hacksaw is mounted in a frame with a horizontal guide. If the motor turns the flywheel at a constant CCW Speed of 60 RPM, find the acceleration (linear) for the position when θ = 90 o . Problem Type: Find: Given: Rigid Body Kinematics ϖ ΟΒ = 60 RPM, α =0 Acceleration of the blade First Step? What do I know in this equation? What do we know here? Does the sign of the cross product make sense? ( 29 B A AB B A AB AB B A r r a a / / ˆ ˆ ˆ ˆ ˆ ˆ ˆ × + × × + = α ϖ Can find r A/B (see triangle). We will talk about how to find ϖ AB next time – for now we are going to assume it is given as 1.432 rad/sec clockwise. How can we find a B ? We have to do another acceleration equation relating B and O . Let’s do it. ( 29 O B OB O B OB OB B r r a a / / ˆ ˆ ˆ ˆ ˆ ˆ ˆ × + × × + = ϖ = 6 0 RPM = 6.283 rad/sec and α = 0 Yes, the only component is the normal acceleration; B is moving in a circular path, so it’s acceleration should be in the -Y direction. Equate the j’s Reflection: The acceleration of the hacksaw is always in the x direction.
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This note was uploaded on 01/22/2011 for the course ME 212 taught by Professor Staff during the Spring '05 term at Cal Poly.

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