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Unformatted text preview: maintaining the same pressure, the volume will be 1. 1201 L. 2. 13.4 L. correct 3. 7.5 L. 4. 50 L. Explanation: T 1 = 25 ◦ C + 273 = 298 K V 1 = 10.0 L T 2 = 125 ◦ C + 273 = 398 K Charles’ law relates the volume and absolute (Kelvin) temperature oF a sample oF gas: V 1 T 1 = V 2 T 2 V 2 = V 1 T 2 T 1 = (10 . 0 L) (398 K) 298 K = 13 . 4 L 005 (part 1 oF 1) 10 points A sample oF a gas occupies 3080 milliliters at 20.0 ◦ C and 4549 torr. What volume would it occupy at the same temperature and 263 torr? Correct answer: 53273 . 5 mL. Explanation: P 1 = 4549 torr P 2 = 263 torr V 1 = 3080 mL Applying Boyle’s Law, P 1 V 1 = P 2 V 2 V 2 = P 1 V 1 P 2 = (4549 torr) (3080 mL) 263 torr = 53273 . 5 mL 006 (part 1 oF 1) 10 points What volume oF hydrogen gas (at STP) would be required to produce 1.00 mole oF HCl?...
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This note was uploaded on 01/23/2011 for the course CH 301 taught by Professor Fakhreddine/lyon during the Spring '07 term at University of Texas.
 Spring '07
 Fakhreddine/Lyon
 Chemistry

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