Exam03answers pg3 - Cheung, Anthony Exam 3 Due: Nov 8 2006,...

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Cheung, Anthony – Exam 3 – Due: Nov 8 2006, 1:00 pm – Inst: McCord 3 010 (part 1 of 1) 10 points You were given the values 0 . 2107, 2 . 253, 3 . 392, and 17 . 58 as the van der Waals parameter a for the gases CO 2 , CH 3 CN, Ne, and CH 4 but NOT the correspondence of the values to the compounds. What a value shoud be assigned to CO 2 ? 1. Unable to determine 2. 0 . 2107 L 2 · atm / mol 3. 2 . 253 L 2 · atm / mol 4. 17 . 58 L 2 · atm / mol 5. 3 . 392 L 2 · atm / mol correct Explanation: Since the van der Waals parameter a rep- resents the role of attractions, it will become larger as the strength of the intermolecular attractions increases. Acetonitrile is polar and would be expected to have the strongest intermolecular forces and the highest value of a . The three non-polar species can be ranked in order of the polarizability of their elec- tron clouds. Carbon dioxide has the largest, most polarizable electron cloud, so it should have the strongest London dispersion forces of these three species and the highest value of
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This note was uploaded on 01/23/2011 for the course CH 301 taught by Professor Fakhreddine/lyon during the Spring '07 term at University of Texas at Austin.

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