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# ch17 - CHAPTER 17 WaveParticle Duality and Quantum Physics...

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CHAPTER 17 Wave–Particle Duality and Quantum Physics 1* · The quantized character of electromagnetic radiation is revealed by ( a ) the Young double-slit experiment. ( b ) diffraction of light by a small aperture. ( c ) the photoelectric effect. ( d ) the J.J. Thomson cathode-ray experiment. ( c ) 2 ·· Two monochromatic light sources, A and B, emit the same number of photons per second. The wavelength of A is l A = 400 nm, and that of B is l B = 600 nm. The power radiated by source B is ( a ) equal to that of source A. ( b ) less than that of source A. ( c ) greater than that of source A. ( d ) cannot be compared to that from source A using the available data. ( b ) 3 · Find the photon energy in joules and in electron volts for an electromagnetic wave of frequency ( a ) 100MHz in the FM radio band, and ( b ) 900 kHz in the AM radio band. ( a ) E = hf ; h = 6.626 × 10 -34 J . s = 4.136 × 10 -15 eV . s ( b ) E = hf E = 6.63 × 10 -26 J = 4.14 × 10 -7 eV E = 5.96 × 10 -28 J = 3.72 × 10 -9 eV 4 · An 80-kW FM transmitter operates at a frequency of 101.1 MHZ. How many photons per second are emitted by the transmitter? P = Nhf ; N = P / hf N = 8 × 10 4 /(6.63 × 10 -34 × 101.1 × 10 6 ) s -1 = 1.19 × 10 30 s -1 5* · What are the frequencies of photons having the following energies? ( a ) 1 eV, ( b ) 1 keV, and ( c ) 1 MeV. ( a ) f = 1/4.14 × 10 -15 Hz = 2.42 × 10 14 Hz. ( b ) f = 2.24 × 10 17 Hz. ( c ) f = 2.24 × 10 20 Hz. 6 · Find the photon energy for light of wavelength ( a ) 450 nm, ( b ) 550 nm, and ( c ) 650 nm. ( a ), ( b ), ( c ) E = hc / l = (1240 eV . nm)/ l ( a ) E = 2.76 eV ( b ) E = 2.25 eV ( c ) E = 1.91 eV 7 · Find the photon energy if the wavelength is ( a ) 0.1 nm (about 1 atomic diameter), and ( b ) 1 fm (1 fm = 10 -15 m, about 1 nuclear diameter). ( a ) E = 1240/0.1 eV = 12.4 keV. ( b ) E = 1240/10 -6 eV = 1.24 GeV.

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