HW6+ChE+150B+F2010+corrected - A typical multi-component...

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ChE 150B Problem Set 6 Due October 10, 2010 Problem 1. (20 Points) The air entering a dryer has a temperature of 65.6 o C and a dew point of 15.6 o C. Using the humidity chart, determine the actual humidity and percentage humidity. Calculate the humid volume of this mixture and c s . Problem 2. (20 Points) Repeat Example 9.9-1 in Geankopolis using the physical properties given but with the following changes. (a) Calculate the time needed to dry the wood from a total moisture of 0.22 to 0.13. (b) Calculate the time needed to dry planks of wood 12.7 mm thick from X t1 = 0.29 to X t = 0.09. Compare with the time needed for 25.4 mm thickness. Problem 3 . (30 Points) In petroleum refineries, a mixture of paraffins and cycloparaffins is commonly reformed in a fixed-bed catalytic reactor to produce blending stocks for gasoline and aromatic precursors for making petrochemicals.
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Unformatted text preview: A typical multi-component product from catalytic reforming is a mixture of ethylbenzene with the three xylene isomers. If this mixture is separated, these four chemicals can be subsequently processed to make styrene, phthalic anhydride, isophthalic acid, and terephthalic acid. Compute, using the following data, the minimum work of separation in Btu/h for T = 560 o R if the mixture below is separated at 20 psia into three products. Split Fraction (SF) Component Feed (lbmol/h) Product 1 Product 2 Product 3 Ethylbenzene 200 0.94 0.06 0.00 p-Xylene 150 0.01 0.98 0.01 m-Xylene 400 0.01 0.98 0.01 o-Xylene 250 0.00 0.02 0.98 Feed Product 1 Product 2 Product 3 Phase condition Liquid Liquid Liquid Liquid Temperature, o F 302 295 302 315 Enthalpy, Btu/lbmol 29,290 29,750 29,550 28,320 Entropy, Btu/lbmol-o R 15.32 12.47 13.6 14.68...
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