finalrevsol2

# finalrevsol2 - Solutions to Final Review Problems Part 2 12...

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12. Let μ be the true mean time to completion for this semester. (a) Hypotheses: H 0 : μ = 35 H a : μ 6 = 35 Test Statistic: t = X - μ 0 S/ n = 38 . 2 - 35 4 . 3 / 20 3 . 33 Rejection Region: Two-tailed from a t -curve with n - 1 = 19 degrees of freedom. The rejection region for α = 0 . 05 is above 2 . 093 and below - 2 . 093. Conclusion: The test statistic is in the rejection region, therefore we reject H 0 in favor of H a at 0 . 05 level of signiFcance. The data suggests that the true mean time to completion this semester is di±erent from past semesters. (b) X ± t α/ 2 ,n - 1 S n 38 . 2 ± (2 . 093) 4 . 3 20 (36 . 18756 , 40 . 21244) (c) Yes, the conFdence interval supports the conclusion from (a) that μ 6 = 35 because 35 is not in this interval of “plausible values” for μ . 13. Let p be the true proportion of adults who will get relief from the drug. ˆ p = 70 / 100 = 0 . 70. (a) Hypotheses:

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## This note was uploaded on 01/23/2011 for the course APPM 5440 at Colorado.

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finalrevsol2 - Solutions to Final Review Problems Part 2 12...

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