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HW01s09_soln

# HW01s09_soln - ECE-2025 Homework#1 Solutions Problem 1.1(a...

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ECE-2025 Homework #1 Solutions Spring-2009 Problem 1.1: (a) A negative real number has a phase (or angle) of π . (b, d, f) Convert to polar first, and then raise to the power by multiplying the angle and raising the angle to the power. (b) ( ) 2 / 2 / 5 2 2 4 / 5 4 / 5 2178 ) 2 ( 33 2 33 2 33 33 33 π π π π j j j j e e e e j = = = (d) ( ) ( ) 2 / 2 / 3 3 3 2 / 3 512 8 8 8 π π π j j j e e e j = = = (f) Use the same strategy. MATLAB verification is given below: %- Problem 1.1 disp('Problem 1.1') zprint([-2*pi, (-33-33i).^2, 1-j*sqrt(3), (-8i).^3, 3-4i, (-3+4i).^7]) Problem 1.1 Z = X + jY Magnitude Phase Ph/pi Ph(deg) -6.283 0 6.283 3.142 1.000 180.00 0 2178 2178 1.571 0.500 90.00 1 -1.732 2 -1.047 -0.333 -60.00 0 512 512 1.571 0.500 90.00 3 -4 5 -0.927 -0.295 -53.13 -7.644e+004 1.612e+004 7.813e+004 2.934 0.934 168.09 Problem 1.2: (a) The angle 6 / 5 π lies in the 3 rd quadrant, so both the real and imaginary parts will be negative. (b) The sum in the exponent can be expanded to a product of exponentials: 4 / 5 π π j e e (c) π π π 5 . 0 ) 36 ( 2 2 / 71 = , so the angle is π 5 . 0 , which means the number has a real part of zero (i.e., is purely imaginary) and its imaginary part is negative. (c) π π π = ) 20 ( 2 41 , so the angle is π , which means the number is a negative real number with no imaginary part. %- Problem 1.2 disp('Problem 1.2') zprint([8*exp(-5i*pi/6), exp(pi-5i*pi/4), pi*exp(71i*pi/2), (pi^exp(1))*exp(- 41i*pi)]) Problem 1.2 Z = X + jY Magnitude Phase Ph/pi Ph(deg) -6.928 -4 8 -2.618 -0.833 -150.00 -16.36 16.36 23.14 2.356 0.750 135.00 3.084e-015 -3.142 3.142 -1.571 -0.500 -90.00 -22.46 -3.521e-013 22.46 -3.142 -1.000 -180.00

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