Unformatted text preview: 2 ] is decreasing at 0.23 M/s, at what rate is [H 2 O] increasing? because [O 2 ] is decreasing, the change in its concentration must be negative, so we substitute the negative value into the expression and solve for Δ[H 2 O]/Δt: ½ Δ[H 2 O]/Δt = –Δ[O 2 ]/Δt = = –(– 0.23 M/s) = 0.23 M/s Δ[H 2 O]/Δt = 2(0.23 M/s) = 0.46 M/s Problem 2 Consider the reaction between NO(g) and O 2 (g) to form N 2 O 3 (g). 1. Express the rate in terms of changes in each reactant and product with time: first, balance the reaction: 4 NO(g) + O 2 (g) → 2 N 2 O 3 (g) Rate = –1/4 Δ[NO]/Δt = –Δ[O 2 ]/Δt = ½ Δ[N 2 O 3 ]/Δt 2. How fast is [O 2 ] decreasing when [NO] is decreasing at a rate of 1.60x104 M/s? –Δ[O 2 ]/Δt = –1/4 Δ[NO]/Δt = –1/4 (–1.60x104 M/s) = 4.00x105 M/s...
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 Spring '10
 BROWN
 4 m/s, Molecule, Monotonic function, 5 m/s, 0.23 m/s, 0.46 m/s

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