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Unformatted text preview: improper integral converges or diverges . If it converges, specify its value. Z t 1 ln x x 2 dx = ( using parts ) =-ln t t-1 t + 1. Therefore, Z 1 ln x x 2 dx = 5. (10) Show all your work in determining the value (if it exists) of the following improper integral. If it diverges show your work in determining this. Z 3 2 3 x-2 dx 6. (8) Use the comparison thoerem, explaining how it applies, to determine whether the integral is convergent or divergent . You DO NOT need to evaluate the integral. (You may use, without proof, any knowledge about convergence or divergence of the improper integrals involving 1 /x , 1 /x 2 , e-x , etc., but be specic.) Z 1 sin 2 x x 2 dx...
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This note was uploaded on 01/24/2011 for the course MATH 21 taught by Professor Mathdep during the Winter '98 term at Missouri S&T.
- Winter '98