7.4.1
1.
I = V/R
I = 12 V / (R1 + R2 + R3)
I = 12 V / ( 104.8 Ω + 209.1 Ω + 310.2 Ω)
I = 12 V / 624.1 Ω
I = .019 A
I = 19 mA
V1 = I x R1
V1 = .019 A x 104.8 Ω
V1 = 1.99 V
V2 = I x R2
V2 = .019 A x 209.1 Ω
V2 = 3.97 v
V3 = I x R3
V3 = .019 A x 310.2 Ω
V3= 5.89 V
2.
(│I – I’│/ I) X 100%
I = 20.0 mA
±
5 mA
I’ = 19.0 mA
(│20.0 mA – 19.0 mA│/ 20.0 mA) X 100% = 5% error
Our error was minimal because our measured value was very close to our calculated value for the
current. This shows that the current is an inverse relationship of Voltage and the combined
resistance.
(│V1 – V1’│/ V1) X 100%
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V1 = 1.98 V
V1’= 1.99 V
(│1.98 – 1.99’│/ 1.98) X 100% = 00.5% Error
Our error was very small because our calculated value was very close to our measured values.
This applies to all three measurements of Voltage in this circuit.
(│V2 – V2’│/ V2) X 100%
V2 = 3.97 V
V2’= 3.97 V
(│3.97 – 3.97│/ 3.97) X 100% = 0% error
(│V3 – V3’│/ V3) X 100%
V3 = 5.91 V
V3’= 5.89V
(│5.91 – 5.89│/ 5.91) X 100% = 00.3% error
3.
(│R – (R1 + R2 + R3│)
/ (R1 + R2 + R3)
R= 624 Ω
(│624
– (104.8 + 209.1 + 310.2)│)
/ (104.8 + 209.1 + 310.2) X 100% = 00.02%
The error of our measurements is almost nonexistent. This proves that the measured total
resistance equals the sum of the individual resistances.
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 Spring '07
 KOPP
 Physics, Resistor, SEPTA Regional Rail, Jaguar Racing, Electrical resistance

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