ch44_p6 - relativistic momentum r mv q B p eB = = γ | |...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
6. (a) In SI units, K = (2200 MeV)(1.6 × 10 –13 J/MeV) = 3.52 × 10 –10 J. Similarly, mc 2 = 2.85 × 10 –10 J for the positive tau. Eq. 37-51 leads to the relativistic momentum: p c KK m c =+ = × ×+ × × −− 1 2 1 2 998 10 3 5 21 0 23 5 21 0 2 8 51 0 22 8 10 2 10 10 . .. . c h c hc h which yields p = 1.90 × 10 –18
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: relativistic momentum: r mv q B p eB = = γ | | where we use the fact that the positive tau has charge e = 1.6 × 10 –19 C. With B = 1.20 T, this yields r = 9.90 m....
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online