9. (a) Conservation of energy gives Q = K2+ K3= E1– E2– E3where Erefers here to the restenergies (mc2) instead of the total energies of the particles. Writing this as K2+ E2– E1= –(K3+ E3) and squaring both sides yields KKEKEEEEE2222211223233322+−+−=++bg. Next, conservation of linear momentum (in a reference frame where particle 1 was at rest) gives |p2| = |p3| (which implies (p2c)2= (p3c)2). Therefore, Eq. 37-54 leads to EE2232+=+which we subtract from the above expression to obtain
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