ch44_p15 - 15. (a) See the solution to Problem 11 for the...

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15. (a) See the solution to Problem 11 for the quantities to be considered, adding strangeness to the list. The lambda has a rest energy of 1115.6 MeV, the proton has a rest energy of 938.3 MeV, and the kaon has a rest energy of 493.7 MeV. The rest energy before the decay is less than the total rest energy after, so energy cannot be conserved. Momentum can be conserved. The lambda and proton each have spin = /2 and the kaon has spin zero, so angular momentum can be conserved. The lambda has charge zero, the proton has charge + e , and the kaon has charge – e , so charge is conserved. The lambda and proton each have baryon number +1, and the kaon has baryon number zero, so baryon number is conserved. The lambda and kaon each have strangeness –1 and the proton has strangeness zero, so strangeness is conserved. Only energy cannot be conserved. (b) The omega has a rest energy of 1680 MeV, the sigma has a rest energy of 1197.3 MeV, and the pion has a rest energy of 135 MeV. The rest energy before the decay is
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This note was uploaded on 01/23/2011 for the course PHY 214 taught by Professor Timothybolton during the Fall '10 term at Kansas State University.

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