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ch44_p23 - never been observed(b Again the particle...

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23. (a) Looking at the first three lines of Table 44-5, since the particle is a baryon, we determine that it must consist of three quarks. To obtain a strangeness of –2, two of them must be s quarks. Each of these has a charge of – e /3, so the sum of their charges is –2 e /3. To obtain a total charge of e , the charge on the third quark must be 5 e /3. There is no quark with this charge, so the particle cannot be constructed. In fact, such a particle has
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Unformatted text preview: never been observed. (b) Again the particle consists of three quarks (and no antiquarks). To obtain a strangeness of zero, none of them may be s quarks. We must find a combination of three u and d quarks with a total charge of 2 e . The only such combination consists of three u quarks....
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