Ch44_p29 - 29(a From f = c and Eq 37-31 we get 0 = 1 1 = 0 1 1 Dividing both sides by 0 leads to 1 =(1 z We solve for 1 1 =(b Now z = 4.43 so(1 z 2

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29. (a) From f = c / λ and Eq. 37-31, we get 00 11 (). ββ −− λ=λ =λ+∆ λ ++ Dividing both sides by λ 0 leads to 1 1 =+ + () . z β We solve for : = +− = + . 2 22 2 2 2 2 z z zz (b) Now z = 4.43, so = + = 443 2 443 2 0 934 2 2 .. b g b g b g b g (c) From Eq. 44-19,
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This note was uploaded on 01/23/2011 for the course PHY 214 taught by Professor Timothybolton during the Fall '10 term at Kansas State University.

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