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# ch44_p29 - 29(a From f = c and Eq 37-31 we get 0 = 1 1 = 0...

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29. (a) From f = c / λ and Eq. 37-31, we get 0 0 1 1 ( ) . 1 1 β β β β λ = λ = λ + ∆λ + + Dividing both sides by λ 0 leads to 1 1 1 1 = + + ( ) . z β β We solve for β : β = + + + = + + + ( ) ( ) . 1 1 1 1 2 2 2 2 2 2 2 z z z z z z (b) Now z = 4.43, so β = + + + = 4 43 2 4 43 4 43 2 4 43
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