41. (a) We use the relativistic relationship between speed and momentum: pmvmvv c==−γ12b g,which we solve for the speed v: vcpcmc=−FHGIKJ+11122.For an antiproton mc2= 938.3 MeV and pc= 1.19 GeV = 1190 MeV, so vcc=−+=111190938 310 7852MeVMeV...bg(b) For the negative pion mc2= 193.6 MeV, and pcis the same. Therefore, vcc=−+=111190193610 9932MeVMeV...bg(c) Since the speed of the antiprotons is about 0.78cbut not over 0.79c, an antiproton will
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