# hw11sol - Solutions to Homework 11 Problem 9.25 For all...

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Solutions to Homework 11 Problem 9.25 For all parts of the problem μ 0 = 45 and n = 36. This means we have n - 1 = 36 - 1 = 35 degrees of freedom for our t distribution. a. The test statistic is t = ¯ x - μ 0 s/ n = 44 - 45 5 . 2 / 36 = - 1 . 15 . The p -value is between 0.10 and 0.15. Since this p -value is greater than α = 0 . 01, we do not reject H 0 and conclude that it is possible the mean is greater than or equal to 45. b. The test statistic is t = ¯ x - μ 0 s/ n = 43 - 45 4 . 6 / 36 = - 2 . 61 . The p -value is between 0.005 and 0.01. Since this p -value is less than α = 0 . 01, we reject H 0 and conclude that the mean is less than 45. c. The test statistic is t = ¯ x - μ 0 s/ n = 46 - 45 5 / 36 = 1 . 2 . The p -value is between 0.90 and 0.85. Since this p -value is greater than α = 0 . 01, we do not reject H 0 and conclude that it is possible the mean is greater than or equal to 45. Problem 9.33

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## This note was uploaded on 01/24/2011 for the course STATISTICS 19897 taught by Professor Jager,abigaill during the Spring '10 term at Kansas State University.

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hw11sol - Solutions to Homework 11 Problem 9.25 For all...

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