# hw11sol - Solutions to Homework 11 Problem 9.25 For all...

This preview shows pages 1–2. Sign up to view the full content.

Solutions to Homework 11 Problem 9.25 For all parts of the problem μ 0 = 45 and n = 36. This means we have n - 1 = 36 - 1 = 35 degrees of freedom for our t distribution. a. The test statistic is t = ¯ x - μ 0 s/ n = 44 - 45 5 . 2 / 36 = - 1 . 15 . The p -value is between 0.10 and 0.15. Since this p -value is greater than α = 0 . 01, we do not reject H 0 and conclude that it is possible the mean is greater than or equal to 45. b. The test statistic is t = ¯ x - μ 0 s/ n = 43 - 45 4 . 6 / 36 = - 2 . 61 . The p -value is between 0.005 and 0.01. Since this p -value is less than α = 0 . 01, we reject H 0 and conclude that the mean is less than 45. c. The test statistic is t = ¯ x - μ 0 s/ n = 46 - 45 5 / 36 = 1 . 2 . The p -value is between 0.90 and 0.85. Since this p -value is greater than α = 0 . 01, we do not reject H 0 and conclude that it is possible the mean is greater than or equal to 45. Problem 9.33

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 2

hw11sol - Solutions to Homework 11 Problem 9.25 For all...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online