ch22_p25 - 25. Studying Sample Problem 22-4, we see that...

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25. Studying Sample Problem 22-4, we see that the field evaluated at the center of curvature due to a charged distribution on a circular arc is given by G E r = λ π 4 0 2 2 ε θ sin / / along the symmetry axis where λ = q / r with in radians. In this problem, each charged quarter-circle produces a field of magnitude [] /4 2 00 || 1 1 22 s i n . /24 4 qq E rr r επ π == G π π ππ That produced by the positive quarter-circle points at – 45°, and that of the negative quarter-circle points at +45°.
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Fall '10 term at Kansas State University.

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