Ch22_p33 - E a – E b E a = 1 − 2 4 ¼ 1 − 2 4 1 = 0.283 or approximately 28 3 3 We use Eq 22-26 noting that the disk in figure b is

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disk in figure ( a ) plus a concentric smaller disk (of radius R /2) with the opposite value of σ . That is, E ( b ) = E ( a ) σ 2 ε o © ¨ § ¹ ¸ · 1 2 R (2 R ) 2 + ( R/ 2) 2 where E ( a ) = σ 2 ε o © ¨ § ¹ ¸ · 1 2 R (2 R ) 2 + R 2 . We find the relative difference and simplify:
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Unformatted text preview: E ( a ) – E ( b ) E ( a ) = 1 − 2 4 + ¼ 1 − 2 4 + 1 = 0.283 or approximately 28%. 3 3. We use Eq. 22-26, noting that the disk in figure ( b ) is effectively equivalent to the...
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Fall '10 term at Kansas State University.

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