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ch22_p40 - 40(a The initial direction of motion is taken to...

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40. (a) The initial direction of motion is taken to be the + x direction (this is also the direction of G E ). We use vv a x fi 22 2 −=∆ with v f = 0 and G G G aFm e Em e == to solve for distance x : x v a mv eE ie i = = = −× × × 31 19 2 911 10 2 160 10 712 10 . . . kg 5.00 10 m s C 1.00 10 N C m. 6 2 3 c hc h c h (b) Eq. 2-17 leads to t x v x v i = × × ∆∆ avg m ms s. 2 2 712 10 500 10 285 10 2 6 8 . . . c h (c) Using v 2 = 2 a x with the new value of x , we find
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