44. We assume there are no forces or force-components along the xdirection. We combine Eq. 22-28 with Newton’s second law, then use Eq. 4-21 to determine time tfollowed by Eq. 4-23 to determine the final velocity (with –greplaced by the ayof this problem); for these purposes, the velocity components givenin the problem statement are re-labeled as v0xand v0yrespectively. (a) We have /( /)aqEme m E== −GGGwhich leads to 19213311.60 10CNˆˆ120j(2.110ms) j.9.11 10kg
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Velocity, Orders of magnitude, The Final, final velocity, 0.020 M