Unformatted text preview: 8.78 × 10 11 m/s 2 ). Thus, Eq. 421 gives t = x v o cos 40 º = 3.00 m 1.53 x 10 7 m/s = 1.96 × 10 − 6 s. This leads (using Eq. 423) to v y = v o sin 40º − a t = − 4.34 × 10 5 m/s . Since the x component of velocity does not change, then the final velocity is v → = (1.53 × 10 6 m/s) i ^ − (4.34 × 10 5 m/s) j ^ ....
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 Fall '10
 Rebello,NobelS
 Charge, Acceleration, Force, 105 m/s, 3.00 m, 107 m/s, 106 m/s

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