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ch22_p47 - 47(a Using Eq 22-28 we find F = 8.00 105 C 3.00...

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G F = × × + × = 8 00 10 8 00 10 600 0 240 0 0480 5 5 . # . # . # . # C 3.00 10 N C i C N C j N i N j. 3 c hc h c hb g b g b g Therefore, the force has magnitude equal to ( ) ( ) 2 2 0.240N 0.0480N 0.245N. F = + = (b) The angle the force F G makes with the + x axis is 1 1 0.0480N tan tan 11.3 0.240N y x F F θ § · § · = = = − ° ¨ ¸ ¨ ¸ © ¹ © ¹ measured counterclockwise from the + x axis. (c) With m = 0.0100 kg, the ( x , y ) coordinates at t = 3.00 s can be found by combining
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