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Unformatted text preview: direction as that of bead 2, in that situation). Comparing the values of E y at 0° and at 90° we see that the absolute values of the charges on beads 1 and 2 must be in the ratio of 5 to 4. This checks with the 180° value from the E x graph, which further confirms our belief that bead 1 is positively charged. In fact, the 180° value from the E x graph allows us to solve for its charge (using Eq. 223): q 1 = 4 πε o r ² E = 4 π ( 8.854 × 10 − 12 C 2 N m 2 )(0.60 m) 2 (5.0 × 10 4 N C ) = 2.0 × 10 − 6 C . (c) Similarly, the 0° value from the E y graph allows us to solve for the charge of bead 2: q 2 = 4 πε o r ² E = 4 π ( 8.854 × 10 − 12 C 2 N m 2 )(0.60 m) 2 (– 4.0 × 10 4 N C ) = –1.6 × 10 − 6 C ....
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Fall '10 term at Kansas State University.
 Fall '10
 Rebello,NobelS

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