# ch22_p57 - 57 Our approach(based on Eq 22-29 consists of...

This preview shows page 1. Sign up to view the full content.

5 7. Our approach (based on Eq. 22-29) consists of several steps. The first is to find an approximate value of e by taking differences between all the given data. The smallest difference is between the fifth and sixth values: 18.08 × 10 –19 C – 16.48 × 10 – 19 C = 1.60 × 10 –19 C which we denote e approx . The goal at this point is to assign integers n using this approximate value of e : 19 1 approx 19 2 approx 19 3 approx 19 4 approx 19 5 approx 6.563 10 C datum1 4.10 4 8.204 10 C datum2 5.13 5 11.50 10 C datum3 7.19 7 13.13 10 C datum4 8.21 8 16.48 10 C datum5 10.30 10 n e n e n e n e n e × = ¡ = × = ¡ = × = ¡ = × = ¡ = × = ¡ = 19 6 appeox 19 7 approx 19 8 approx 19 9 approx 18.08 10 C datum6 11.30 11 19.71 10 C datum7 12.32 12 22.89 10 C datum8 14.31 14 26.13 10 C datum9 16.33 16 n e n e n e n e × = ¡ = × = ¡ = × = ¡ = × = ¡ = Next, we construct a new data set ( e 1 , e 2 , e 3 …) by dividing the given data by the
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Fall '10 term at Kansas State University.

Ask a homework question - tutors are online