ch22_p62 - 62. We use Eq. 22-16, with q denoting the charge...

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Q z 4 πε o ( z 2 + R 2 ) 3/2 + q z 4 πε o ( z 2 + (3 R ) 2 ) 3/2 = 0 ¡ q = Q © ¨ § ¹ ¸ · 13 13 5 5 which gives q 4.19 Q . Note: we set z = 2 R in the above calculation.
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