66. (a) The electron ecis a distance r= z= 0.020 meter away. Thus, Ec= e4πεo r2= 3.60×10− 6 N/C . (b) The horizontal components of the individual fields (due to the two escharges) cancel, and the vertical components add to give Es, net= 2 e z4πεo (R2+ z2)3/2= 2.55×10−6 N/C . (c) Calculation similar to that shown in part (a) now leads to a stronger field 43.60 10 N/CcE−=×from the central charge. (d) The field due to the side charges may be obtained from calculation similar to that shown in part (b). The result is
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Fall '10 term at Kansas State University.