This preview shows page 1. Sign up to view the full content.
we can relate it to the magnitude of the field).
Sample Problem 224 illustrates the
simplest approach to circular arc field problems.
Following the steps leading to Eq. 22
21, we see that the general result (for arcs that subtend angle
θ
) is
E =
λ
4
πε
o
r
[sin(
θ/2) −
sin(
−θ/2)
]
=
λ
sin
(θ/2)
2
πε
o
r
.
Now, the arc length is
L = r
if
is expressed in radians
.
Thus, using
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Fall '10 term at Kansas State University.
 Fall '10
 Rebello,NobelS
 Charge

Click to edit the document details