ch22_p67 - 67. We interpret the linear charge density, =| Q...

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we can relate it to the magnitude of the field). Sample Problem 22-4 illustrates the simplest approach to circular arc field problems. Following the steps leading to Eq. 22- 21, we see that the general result (for arcs that subtend angle θ ) is E = λ 4 πε o r [sin( θ/2) − sin( −θ/2) ] = λ sin (θ/2) 2 πε o r . Now, the arc length is L = r if is expressed in radians . Thus, using
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Fall '10 term at Kansas State University.

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