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78. Studying Sample Problem 224, we see that the field evaluated at the center of
curvature due to a charged distribution on a circular arc is given by
G
E
r
=
−
λ
π
4
0
2
2
ε
θ
sin
along the symmetry axis
where
λ=
=
qq
r
A
with
in radians. Here
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 Fall '10
 Rebello,NobelS
 Charge

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