78. Studying Sample Problem 224, we see that the field evaluated at the center of
curvature due to a charged distribution on a circular arc is given by
G
E
r
=
−
λ
π
4
0
2
2
ε
θ
sin
along the symmetry axis
where
λ=
=
qq
r
A
with
in radians. Here
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Fall '10 term at Kansas State University.
 Fall '10
 Rebello,NobelS
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