ch22_p83 - 83. (a) For point A, we have (in SI units) EA =...

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83. (a) For point A , we have (in SI units) () ( ) 12 22 01 02 91 2 9 1 2 ˆ i 44 8.99 10 1.00 10 C 8.99 10 | 2.00 10 C| ˆˆ ii 5.00 10 2 5.00 10 ˆ ( 1.80 N C)i. A qq E rr πε −− ªº =+ «» ¬¼ ×× × × =− + × G . (b) Similar considerations leads to ( ) 2 9 1 2 8.99 10 1.00 10 C 8.99 10 | 2.00 10 C| || ˆ i 0.500 5.00 10 0.500 5.00 10 ˆ (43.2 N C)i. B E × × = + = G (c) For point C, we have ( ) 2 9 1 2 8.99 10 1.00 10 C 8.99 10 | 2.00 10 C| ˆ i 2.00 5.00 10 5.00 10 ˆ (6.29 N C)i. C E × × = × G (d) Although a sketch is not shown here, it would be somewhat similar to Fig. 22-5 in the textbook except that there would be twice as many field lines “coming into” the negative
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