ch22_p84 - 84. The electric field at a point on the axis of...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
E qz zR = + 4 0 22 32 π ε c h / where q is the charge on the ring and R is the radius of the ring (see Eq. 22-16). For q positive, the field points upward at points above the ring and downward at points below the ring. We take the positive direction to be upward. Then, the force acting on an electron on the axis is F eqz =− + 4 0 π c h / . For small amplitude oscillations z R << and z can be neglected in the denominator. Thus, F eqz R 4 0 3 π . The force is a restoring force: it pulls the electron toward the equilibrium point
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Fall '10 term at Kansas State University.

Ask a homework question - tutors are online