ch22_p86 - 86. (a) The electric field is upward in the...

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86. (a) The electric field is upward in the diagram and the charge is negative, so the force of the field on it is downward. The magnitude of the acceleration is a = eE / m , where E is the magnitude of the field and m is the mass of the electron. Its numerical value is a = ×× × 160 10 911 10 351 10 19 31 14 . . .. C2 . 0 01 0NC kg ms 3 2 c hc h We put the origin of a coordinate system at the initial position of the electron. We take the x axis to be horizontal and positive to the right; take the y axis to be vertical and positive toward the top of the page. The kinematic equations are 2 00 0 1 cos , sin , and sin . 2 y xv t y v t at v v at θθ θ == = First, we find the greatest y coordinate attained by the electron. If it is less than d , the electron does not hit the upper plate. If it is greater than d , it will hit the upper plate if the corresponding x coordinate is less than L . The greatest y coordinate occurs when v y = 0. This means v 0 sin at = 0 or t = ( v 0 / a ) sin and () 2 62 22 2 0 max 2 2 14 6.00 10 m s sin 45
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Fall '10 term at Kansas State University.

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ch22_p86 - 86. (a) The electric field is upward in the...

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