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ch23_p20 - 20 We imagine a cylindrical Gaussian surface A...

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20. We imagine a cylindrical Gaussian surface A of radius r and unit length concentric with the metal tube. Then by symmetry enc 0 2 . A q E dA rE ε = π = ³ G G v (a) For r < R, q enc = 0, so E = 0. (b) For r > R, q enc = λ , so 0 ( ) / 2 . E r r π ε = λ With 8 2.00 10 C/m λ = × and r = 2.00 R = 0.0600 m, we obtain ( ) ( ) ( ) 8 3 12 2 2 2.0 10 C/m 5.99 10
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