ch23_p29 - 29. We denote the radius of the thin cylinder as...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 29. We denote the radius of the thin cylinder as R = 0.015 m. Using Eq. 23-12, the net electric field for r > R is given by Enet = Ewire + Ecylinder = −λ λ′ + 2πε 0 r 2πε 0 r where –λ = –3.6 nC/m is the linear charge density of the wire and λ' is the linear charge density of the thin cylinder. We note that the surface and linear charge densities of the thin cylinder are related by qcylinder = λ′ L = σ (2πRL) λ′ = σ (2πR). Now, Enet outside the cylinder will equal zero, provided that 2πRσ = λ, or σ= λ 3.6 × 10−6 C/m = = 3.8 × 10−8 C/m 2 . 2π R (2π)(0.015 m) ...
View Full Document

Ask a homework question - tutors are online