Unformatted text preview: 29. We denote the radius of the thin cylinder as R = 0.015 m. Using Eq. 2312, the net electric field for r > R is given by
Enet = Ewire + Ecylinder = −λ λ′ + 2πε 0 r 2πε 0 r where –λ = –3.6 nC/m is the linear charge density of the wire and λ' is the linear charge density of the thin cylinder. We note that the surface and linear charge densities of the thin cylinder are related by
qcylinder = λ′ L = σ (2πRL) λ′ = σ (2πR). Now, Enet outside the cylinder will equal zero, provided that 2πRσ = λ, or σ= λ 3.6 × 10−6 C/m = = 3.8 × 10−8 C/m 2 . 2π R (2π)(0.015 m) ...
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.
 Spring '10
 Rebello,NobelS
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