ch23_p30 - 30. To evaluate the field using Gauss law, we...

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30. To evaluate the field using Gauss’ law, we employ a cylindrical surface of area 2 π r L where L is very large (large enough that contributions from the ends of the cylinder become irrelevant to the calculation). The volume within this surface is V = π r 2 L , or expressed more appropriate to our needs: dV = 2 π r L dr . The charge enclosed is, with 65 2.5 10 C/m A , 24 enc 0 2. 2 r qA r r L d r A L r π = ³ By Gauss’ law, we find
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