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# ch23_p30 - 30 To evaluate the field using Gauss law we...

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30. To evaluate the field using Gauss’ law, we employ a cylindrical surface of area 2 π r L where L is very large (large enough that contributions from the ends of the cylinder become irrelevant to the calculation). The volume within this surface is V = π r 2 L , or expressed more appropriate to our needs: dV = 2 π r L dr . The charge enclosed is, with 6 5 2.5 10 C/m A = × , 2 4 enc 0 2 . 2 r q Ar r L dr ALr π = π = ³ By Gauss’ law, we find
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