ch23_p40 - x 0.691 m) is in the forbidden region between...

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40. The point where the individual fields cancel cannot be in the region between the sheet and the particle ( d < x < 0) since the sheet and the particle have opposite-signed charges. The point(s) could be in the region to the right of the particle ( x > 0) and in the region to the left of the sheet ( x < d ); this is where the condition | σ | 2 ε ο = Q 4 πε o r 2 must hold. Solving this with the given values, we find r = x = ± 3/2 π ± 0.691 m. If d = 0.20 m (which is less than the magnitude of r found above), then neither of the points (
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Unformatted text preview: x 0.691 m) is in the forbidden region between the particle and the sheet. Thus, both values are allowed. Thus, we have (a) x = 0.691 m on the positive axis, and (b) x = 0.691 m on the negative axis. (c) If, however, d = 0.80 m (greater than the magnitude of r found above), then one of the points ( x 0.691 m) is in the forbidden region between the particle and the sheet and is disallowed. In this part, the fields cancel only at the point x + 0.691 m....
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