ch23_p42 - r = 0.020 m). Thus, E = q 4 o r 2 q = 2.2 10 6 C...

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42. We determine the (total) charge on the ball by examining the maximum value ( E = 5.0 × 10 7 N/C) shown in the graph (which occurs at
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Unformatted text preview: r = 0.020 m). Thus, E = q 4 o r 2 q = 2.2 10 6 C ....
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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