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Unformatted text preview: Consequently, the point should be in the region to the left of shell 1 (at a distance r > R 1 from its center); this is where the condition E 1 = E 2  q 1  4 o r 2 =  q 2  4 o ( r + L) 2 or 1 A 1 4 o r 2 =  2  A 2 4 o ( r + L) 2 . Using the fact that the area of a sphere is A = 4 R 2 , this condition simplifies to r = L ( R 2 / R 1 )  2 / 1 1 = 3.3 cm . We note that this value satisfies the requirement r > R 1 . The answer, then, is that the net field vanishes at x = r = 3.3 cm....
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.
 Spring '10
 Rebello,NobelS
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