ch23_p53 - 53. We use E (r ) = qencl 1 = 2 4 0 r 4 0 r 2 r...

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5 3. We use 2 encl 22 0 00 1 () ()4 44 r q Er r rd r rr ρ εε == ³ π ππ to solve for ( r ): ε . r r d dr rEr r d dr Kr
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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