ch23_p56 - (b At r = R/2 the magnitude of the field is E =...

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56. (a) Since the volume contained within a radius of 1 2 R is one-eighth the volume contained within a radius of R , so the charge at 0 < r < R /2 is Q /8. The fraction is 1/8 = 0.125.
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Unformatted text preview: (b) At r = R /2, the magnitude of the field is E = Q /8 4 πε o ( R /2) 2 = Q 8 πε o R 2 and is equivalent to half the field at the surface. Thus, the ratio is 0.500....
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This note was uploaded on 01/25/2011 for the course PHYSICS 17029 taught by Professor Rebello,nobels during the Spring '10 term at Kansas State University.

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