Unformatted text preview: Q distributed uniformly on the inner surface. Thus, the answer is +1.2 × 10 − 9 C. (d) Since the total excess charge on the conductor is q and is located on the surfaces, then the outer surface charge must equal the total minus the inner surface charge. Thus, the answer is 2.0 × 10 − 9 C – 1.2 × 10 − 9 C = +0.80 × 10 − 9 C. 6 1. The initial field (evaluated “just outside the outer surface” which means it is...
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 Spring '10
 Rebello,NobelS
 Charge, Kompakt, hollow conductor

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